Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set - Page 105: 8

Answer

$[-3,4.2]$ or $[-3,4\frac{1}{5}]$ Graph :

Work Step by Step

$|5x-3 | \leq 18$ This is equivalent to $-18 \leq 5x-3 \leq 18$ [Using the property, $|X| \leq a = −a\leq x \leq a$] By the inequality property, add $3$ to all parts. $-18+3 \leq 5x-3+3 \leq 18+3$ $-15 \leq 5x \leq 21$ Divide by $5$ $-3 \leq x \leq \frac{21}{5}$ or $-3 \leq x \leq 4\frac{1}{5}$ or $-3 \leq x \leq 4.2$ Interval Notation : $[-3,4.2]$
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