Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set - Page 105: 14

Answer

Interval Notation : $(-6,2)$ Graph:

Work Step by Step

$|z+2| - 7 \lt -3$ Isolate absolute value expression by adding $7$ to both sides, $|z+2| - 7+7 \lt -3+7$ $|z+2| \lt 4$ Using the absolute value inequality property, we can write it as $-4 \lt z+2 \lt 4$ Add $-2$ to all parts. $-4-2 \lt z+2-2 \lt 4-2 $ $-6 \lt z \lt 2$ Interval notation: $(-6,2)$
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