Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.2 - An Introduction to Problem Solving - Exercise Set - Page 68: 84

Answer

$500$ computer boards; \$30,000

Work Step by Step

Equating the cost expression, $C=50x+5000$, and the revenue expression, $60x,$ then the number of computer boards, $x$, to break even is \begin{array}{l}\require{cancel} 50x+5000=60x \\\\ 50x-60x=-5000 \\\\ -10x=-5000 \\\\ x=\dfrac{-5000}{-10} \\\\ x=500 .\end{array} Hence, $\text{ $500$ computer boards }$ are needed to be sold to break even. Substituting $x=500$ in the cost expression, then the amount needed to produce the break-even number of boards is \begin{array}{l}\require{cancel} 50(500)+5000 \\\\= 25000+5000 \\\\= 30,000 .\end{array} Hence, $ \$30,000 $ is needed.
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