## Intermediate Algebra (6th Edition)

Let $x$ and $x+2$ be the odd consecutive integers. Based on the conditions of the problem, then, \begin{array}{l}\require{cancel} 7x=5(x+2)+54 \\\\ 7x=5x+10+54 \\\\ 7x-5x=64 \\\\ 2x=64 \\\\ x=\dfrac{64}{2} \\\\ x=32 .\end{array} Since the solution gives an even number, then no such numbers exist that satisfy the conditions of the problem.