Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Sections 1.2-1.3 - Integrated Review - Algebraic Expressions and Operations on Whole Numbers: 9



Work Step by Step

We are asked to evaluate $\sqrt 64-\sqrt[3] 64$. We know that $\sqrt 64=8$, because $8^{2}=8\times8=64$ And we know that $\sqrt[3] 64=4$, because $4^{3}=4\times4\times4=64$ Therefore, $\sqrt 64-\sqrt[3] 64=8-4=4$
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