Answer
35
Work Step by Step
$9+2[(8-10)^{2}+(-3)^{2}]=9+2\times[(8-10)^{2}+(-3)^{2}]$
To evaluate the expression, we must first evaluate the terms within parentheses.
$9+2\times[(-2)^{2}+(-3)^{2}]=9+2\times[(-2\times-2)+(-3\times-3)]=9+2\times[4+9]$
Next, we must perform the operation in brackets.
$9+2\times[13]$
Finally, we perform the last operations.
$9+26=35$
