Answer
$\left(1,0\right)$
Work Step by Step
To find the vertex of the given equation, $
f(x)=-(x-1)^2
,$ convert the equation in the form $y=a(x-h)^2+k$. That is, the given equation is equivalent to
\begin{align*}
f(x)&=-(x-1)^2+0
.\end{align*}
Since the vertex of the equation $y=a(x-h)^2+k$ is given by $(h,k)$, then the vertex of the quadratic equation above is $
\left(1,0\right)
$.
