Answer
TRUE
Work Step by Step
Using the properties of logarithms, the left-hand expression, $
\log_3 8+\log_3 \dfrac{1}{8}
$, is equivalent to
\begin{align*}
&
\log_3 \left(8\cdot\dfrac{1}{8}\right)
&(\text{use }\log_b (xy)=\log_b x+\log_b y)
\\\\&=
\log_3 1
\\&=
0
&(\text{use }\log_b 1=0)
.\end{align*}
Thus, the left-hand expression is equivalent to the given right-hand expression. Hence, the given statement is true.