#### Answer

-.6532

#### Work Step by Step

We are given that $log_{10}2=.3010$ and $log_{10}9=.9542$.
We know that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{10}\frac{2}{9}=log_{10}2-log_{10}9=.3010-.9542=-.6532$.