## Intermediate Algebra (12th Edition)

$x=-3$
We are given the equation $5^{x}=\frac{1}{125}$. First, we must write both sides using the same base. $5^{x}=5^{-3}=\frac{1}{125}$ Next, we must take the natural log of both sides. $ln(5^{x})=ln(5^{-3})$ $xln(5)=-3ln(5)$ Divide both sides by $ln(5)$. $x=-3$