Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.2 - Exponential Functions - 9.2 Exercises - Page 597: 25

Answer

Graph of $f(x)=2^{2x-2}$

Work Step by Step

Substituting values of $x$ in the given function, $ f(x)=2^{2x-2} $, results to \begin{array}{c|c|c} \text{If }x=-1: & \text{If }x=0 & \text{If }x=1 \\\\ f(x)=y=2^{2x-2} & f(x)=y=2^{2x-2} & f(x)=y=2^{2x-2} \\ y=2^{2(-1)-2} & y=2^{2(0)-2} & y=2^{2(1)-2} \\ y=2^{-2-2} & y=2^{0-2} & y=2^{2-2} \\ y=2^{-4} & y=2^{-2} & y=2^{0} \\ y=\dfrac{1}{2^4} & y=\dfrac{1}{2^2} & y=1 \\ y=\dfrac{1}{16} & y=\dfrac{1}{4} .\end{array} Tabulating the results above results to the table below. \begin{array}{c|c} \hline x & y \\\hline -1 & \dfrac{1}{16} \\\hline 0 & \dfrac{1}{4} \\\hline 1 & 1 \end{array} Connecting the points $ \left(-1,\dfrac{1}{16}\right), \left(0,\dfrac{1}{4}\right), \text{ and } \left(1,1\right) $ with a curve gives the graph of $ f(x)=2^{2x-2} $.
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