Answer
$\left(-\infty,-3\right)\cup\left(2,\infty\right)$
Work Step by Step
Since $|x|>c$ (where $c$ is a positive constant) implies $xc$, then the given equation, $
|4x+2|>10
$, implies
\begin{align*}\require{cancel}
4x+210
.\end{align*}
Solving each equation results to
\begin{array}{l|r}
4x10-2
\\
4x8
\\\\
\dfrac{\cancel4x}{\cancel4}\dfrac{8}{4}
\\\\
x2
.\end{array}
Hence, in interval solution, the solution set of the inequality, $
|4x+2|>10
$ is $
\left(-\infty,-3\right)\cup\left(2,\infty\right)
$.
