Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Chapter R-9 - Cumulative Review Exercises - Page 641: 4

Answer

$16$

Work Step by Step

Since $|c|=+c$, where $c$ is a constant, then the given expression, $ |-8|+6-|-2|-(-6+2) $, is equivalent to \begin{align*} 8+6-2-(-6+2) .\end{align*} Using order of operations, the expression above simplifies to \begin{align*} & 8+6-2-(-4) \\&= 8+6-2+4 \\&= 14-2+4 \\&= 12+4 \\&= 16 .\end{align*} Hence, the expression $ |-8|+6-|-2|-(-6+2) $ simplifies to $ 16 $.
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