Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Section 8.4 - Formulas and Further Applications - 8.4 Exercises - Page 536: 5

Answer

$m=\sqrt{p^2-n^2}$

Work Step by Step

Using $a^2+b^2=c^2$ or the Pythagorean Theorem, the relationship of the sides of the given right triangle is \begin{align*} m^2+n^2&=p^2 .\end{align*} Using the properties of equality to isolate $m^2$ results to \begin{align*} m^2&=p^2-n^2 .\end{align*} Taking the square root of both sides (Square Root Property), the equation above is equivalent to \begin{align*} m&=\pm\sqrt{p^2-n^2} .\end{align*} Since $m$ should be greater than zero and $p$ is the longest side (i.e. $p$ is the hypotenuse), then \begin{align*} m&=\sqrt{p^2-n^2} .\end{align*}
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