Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Section 8.4 - Formulas and Further Applications - 8.4 Exercises: 19

Answer

$h=\dfrac{D^2}{k}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ D=\sqrt{kh} ,$ in terms of $ h ,$ square both sides. Then use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Squaring both sides, the equation above is equivalent to \begin{array}{l}\require{cancel} (D)^2=\left(\sqrt{kh}\right)^2 \\\\ D^2=kh .\end{array} Using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} \dfrac{D^2}{k}=h \\\\ h=\dfrac{D^2}{k} .\end{array}
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