Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.4 - Adding and Subtracting Radical Expressions - 7.4 Exercises - Page 466: 19

Answer

$4\sqrt{2x}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given radical expression, $ \sqrt{72x}-\sqrt{8x} ,$ simplify first each term by expressing the radicand as a factor that is a perfect power of the index. Then, extract the root. Finally, combine the like radicals. $\bf{\text{Solution Details:}}$ Expressing the radicand as an expression that contains a factor that is a perfect power of the index results to \begin{array}{l}\require{cancel} \sqrt{36\cdot2x}-\sqrt{4\cdot2x} \\\\= \sqrt{(6)^2\cdot2x}-\sqrt{(2)^2\cdot2x} .\end{array} Extracting the roots of the factor that is a perfect power of the index results to \begin{array}{l}\require{cancel} 6\sqrt{2x}-2\sqrt{2x} .\end{array} By combining like radicals, the expression above is equivalent to \begin{array}{l}\require{cancel} (6-2)\sqrt{2x} \\\\= 4\sqrt{2x} .\end{array}
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