Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.4 - Adding and Subtracting Radical Expressions - 7.4 Exercises - Page 465: 9

Answer

$14\sqrt[3] 2$

Work Step by Step

$\sqrt[3] 16+4\sqrt[3] 54=\sqrt[3] (8\times2)+4\sqrt[3] (27\times2)=\sqrt[3] 8\times\sqrt[3] 2+4\times\sqrt[3] 27\times\sqrt[3] 2=2\times\sqrt[3] 2+4\times3\times\sqrt[3] 2=2\sqrt[3] 2+12\sqrt[3] 2=14\sqrt[3] 2$
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