Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.4 - Adding and Subtracting Radical Expressions - 7.4 Exercises: 8

Answer

$12\sqrt 2$

Work Step by Step

$4\sqrt 32-2\sqrt8=4\sqrt (16\times2)-2\sqrt (4\times2)=4\times\sqrt 16\times\sqrt 2-2\times\sqrt 4\times\sqrt 2=4\times4\times\sqrt 2-2\times2\times\sqrt 2=16\sqrt 2-4\sqrt 2=12\sqrt 2$
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