Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 460: 69


$6k\sqrt 2$

Work Step by Step

$\sqrt (72k^{2})=\sqrt (36\times k^{2}\times2)=\sqrt 36\times\sqrt k^{2}\times\sqrt 2=6k\sqrt 2$ We know that $\sqrt 36=6$, because $6^{2}=36$. We know that $\sqrt k^{2}=k$, because $(k)^{2}=k^{2}$.
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