## Intermediate Algebra (12th Edition)

$(x^2+4)(1+y)$
$\bf{\text{Solution Outline:}}$ Group the terms of the given expression, $x^2+4+x^2y+4y ,$ such that the factored form of the groupings will result to a factor that is common to the entire expression. Then, factor the $GCF$ in each group. Finally, factor the $GCF$ of the entire expression. $\bf{\text{Solution Details:}}$ Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} (x^2+4)+(x^2y+4y) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} (x^2+4)+y(x^2+4) .\end{array} Factoring the $GCF= (x^2+4)$ of the entire expression above results to \begin{array}{l}\require{cancel} (x^2+4)(1+y) .\end{array}