## Intermediate Algebra (12th Edition)

$\bf{\text{Solution Outline:}}$ The given expression, $k^2-6k+16 ,$ is prime. $\bf{\text{Solution Details:}}$ In the trinomial expression above, $b= -6 ,\text{ and } c= 16 .$ Using the factoring of trinomials in the form $x^2+bx+c,$ there are no two numbers whose product is $c$ and whose sum is $b.$ Hence, the given expression is $\text{ not factorable .}$