## Intermediate Algebra (12th Edition)

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$\bf{\text{Solution Outline:}}$ Substitute the given value of the variables and then use the order of operations (PEMDAS - Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction) to evaluate the given expression, $\dfrac{\sqrt{r}}{-p+2q} .$ $\bf{\text{Solution Details:}}$ Substituting $p=-4,q=-2,$ and $r=5,$ the given expression evaluates to \begin{array}{l}\require{cancel} \dfrac{\sqrt{5}}{-(-4)+2(-2)} .\end{array} Simplifying the expressions in parenthesis, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{\sqrt{5}}{4+2(-2)} .\end{array} Simplifying the products, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{\sqrt{5}}{4-4} .\end{array} Simplifying the sums/differences, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{\sqrt{5}}{0} .\end{array} Since division by zero is not allowed, then the value of the given expression is $\text{undefined} .$