Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Chapters R-5 - Cumulative Review Exercises - Page 363: 18


$x-\text{intercept is } -\dfrac{7}{2} \text{ or } \left( -\dfrac{7}{2},0 \right) $

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the definition of $x-$intercept (the value of $x$ when $y$ or $f(x)$ is $0$), to find the $x-$intercept of $ f(x)=2x+7 .$ $\bf{\text{Solution Details:}}$ Replacing $f(x)$ with zero, then \begin{array}{l}\require{cancel} 0=2x+7 \\\\ -2x=7 \\\\ x=\dfrac{7}{-2} \\\\ x=-\dfrac{7}{2} .\end{array} Hence the $ x-\text{intercept is } -\dfrac{7}{2} \text{ or } \left( -\dfrac{7}{2},0 \right) .$
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