Answer
$-\frac{9}{4}$
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We are asked to find the value of $(g+h)(\frac{1}{4})$. We know that $(g+h)(x)=g(x)+h(x)$.
Therefore, $(g+h)(\frac{1}{4})=(2(\frac{1}{4}))+(\frac{1}{4}-
\frac{12}{4})=(\frac{2}{4})+(\frac{1-12}{4})=(\frac{2}{4})+(\frac{-11}{4})=\frac{2}{4}-\frac{11}{4}=\frac{2-11}{4}=\frac{-9}{4}=-\frac{9}{4}$.