Answer
-10
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We are asked to find the value of $(f+h)(-2)$. We know that $(f+h)(x)=f(x)+h(x)$.
Therefore, $(f+h)(-2)=((-2)^{2}-9)+(-2-3)=(4-9)+(-5)=(-5)-5=-5-5=-10$.