Answer
a. -11, b. 4, c. -8
Work Step by Step
We are given the function $f(x)=-x^{2}+2x^{3}-8$. In order to find the specified values, we can plug the values into the function and solve.
a. $f(-1)= -(-1)^{2}+2(-1)^{3}-8=(-1\times1)+(2\times-1)-8=(-1)+(-2)-8=-1-2-8=-11$
b. $f(2)= -(2)^{2}+2(2)^{3}-8=(-1\times4)+(2\times8)-8=(-4)+(16)-8=-4+16-8=4$
c. $f(0)= -(0)^{2}+2(0)^{3}-8=(-1\times0)+(2\times0)-8=(0)+(0)-8=0+0-8=-8$
