Answer
a. 5, b. 71, c. -1
Work Step by Step
We are given the function $f(x)=4x^{4}+2x^{2}-1$. In order to find the specified values, we can plug the values into the function and solve.
a. $f(-1)= 4(-1)^{4}+2(-1)^{2}-1=(4\times1)+(2\times1)-1=(4)+(2)-1=4+2-1=5$
b. $f(2)= 4(2)^{4}+2(2)^{2}-1=(4\times16)+(2\times4)-1=(64)+(8)-1=64+8-1=71$
c. $f(0)= 4(0)^{4}+2(0)^{2}-1=(4\times0)+(2\times0)-1=(0)+(0)-1=0+0-1=-1$
