Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.2 - Adding and Subtracting Polynomials - 4.2 Exercises - Page 285: 59

Answer

$r+13$

Work Step by Step

Removing the grouping symbols and then combining like terms, the given expression, $ (3r+8)-(2r-5) ,$ simplifies to \begin{array}{l}\require{cancel} 3r+8-2r+5 \\\\= (3r-2r)+(8+5) \\\\= r+13 .\end{array}
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