Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 279: 175



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{3\times10^{-2}}{12\times10^3} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{3}{12}\times10^{-2-3} \\\\= \dfrac{1}{4}\times10^{-5} \\\\= 0.25\times10^{-5} .\end{array} Since the exponent of $10$ is $\text{negative } 5 ,$ move the decimal point $ 5 $ places to the $\text{left.}$ Hence, the standard form of the expression above is \begin{array}{l}\require{cancel} 0.000025 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.