Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 176

Answer

$0.00002$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{5\times10^{-3}}{25\times10^2} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{5}{25}\times10^{-3-2} \\\\= \dfrac{1}{5}\times10^{-5} \\\\= 0.2\times10^{-5} .\end{array} Since the exponent of $10$ is $\text{negative } 5 ,$ move the decimal point $ 5 $ places to the $\text{left.}$ Hence, the standard form of the expression above is \begin{array}{l}\require{cancel} 0.00002 .\end{array}
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