Answer
$0.00002$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{5\times10^{-3}}{25\times10^2}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{5}{25}\times10^{-3-2}
\\\\=
\dfrac{1}{5}\times10^{-5}
\\\\=
0.2\times10^{-5}
.\end{array}
Since the exponent of $10$ is $\text{negative }
5
,$ move the decimal point $
5
$ places to the $\text{left.}$ Hence, the standard form of the expression above is
\begin{array}{l}\require{cancel}
0.00002
.\end{array}
