Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Chapter 4 Test: 15

Answer

$9k^2+6kq+q^2$

Work Step by Step

Use special products to multiply the given expression, $ (3k+q)^2 .$ Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the product of the expression above is \begin{array}{l}\require{cancel} (3k)^2+2(3k)(q)+(q)^2 \\\\= 9k^2+6kq+q^2 .\end{array}
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