## Intermediate Algebra (12th Edition)

$9k^2+6kq+q^2$
Use special products to multiply the given expression, $(3k+q)^2 .$ Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the product of the expression above is \begin{array}{l}\require{cancel} (3k)^2+2(3k)(q)+(q)^2 \\\\= 9k^2+6kq+q^2 .\end{array}