Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Chapter 4 Test: 14

Answer

$36x^2-y^2$

Work Step by Step

Use special products to multiply the given expression, $ (6x+y)(6x-y) .$ Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the product of the expression above is \begin{array}{l}\require{cancel} (6x)^2-(y)^2 \\\\= 36x^2-y^2 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.