## Intermediate Algebra (12th Edition)

$36x^2-y^2$
Use special products to multiply the given expression, $(6x+y)(6x-y) .$ Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the product of the expression above is \begin{array}{l}\require{cancel} (6x)^2-(y)^2 \\\\= 36x^2-y^2 .\end{array}