## Intermediate Algebra (12th Edition)

$y=-x+2$
The given graph of a line passes through the points $( 0,2 )$ and $( 3,-1 ).$ Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, then the equation of the line is \begin{array}{l}\require{cancel} y-2=\dfrac{2-(-1)}{0-3}(x-0) \\\\ y-2=\dfrac{2+1}{0-3}(x) \\\\ y-2=\dfrac{3}{-3}x \\\\ y-2=-1x \\\\ y=-x+2 .\end{array}