Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 26

Answer

$y=-x+2$

Work Step by Step

The given graph of a line passes through the points $( 0,2 )$ and $( 3,-1 ).$ Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, then the equation of the line is \begin{array}{l}\require{cancel} y-2=\dfrac{2-(-1)}{0-3}(x-0) \\\\ y-2=\dfrac{2+1}{0-3}(x) \\\\ y-2=\dfrac{3}{-3}x \\\\ y-2=-1x \\\\ y=-x+2 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.