#### Answer

$y=\dfrac{2}{3}x+1$

#### Work Step by Step

The given graph of a line passes through the points $(
0,1
)$ and $(
3,3
).$ Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, then the equation of the line is
\begin{array}{l}\require{cancel}
y-1=\dfrac{1-3}{0-3}(x-0)
\\\\
y-1=\dfrac{-2}{-3}(x)
\\\\
y-1=\dfrac{2}{3}x
\\\\
y=\dfrac{2}{3}x+1
.\end{array}