Answer
$\left( -2,2 \right)$
Work Step by Step
$\bf{\text{Solution Outline:}}$
Use the concepts of inequalities to translate the given description,
\begin{array}{l}\require{cancel}\text{
6 times a number is between $-12$ and $12$
},\end{array}
into symbols. Then solve using the properties of inequality. Express the solution set in interval notation.
$\bf{\text{Solution Details:}}$
In symbols, the given description translates to
\begin{array}{l}\require{cancel}
-12 \lt 6x \lt 12
.\end{array}
Using the properties of inequality, the inequality above is equivalent to
\begin{array}{l}\require{cancel}
-\dfrac{12}{6} \lt \dfrac{6x}{6} \lt \dfrac{12}{6}
\\\\
-2 \lt x \lt 2
.\end{array}
In interval notation, the solution set is $
\left( -2,2 \right)
.$