## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 1 - Review Exercises: 73

no solution

#### Work Step by Step

The given inequality, $|3-4x|+7\lt-4 ,$ is equivalent to \begin{array}{l}\require{cancel} |3-4x|\lt-4-7 \\\\ |3-4x|\lt-11 .\end{array} For any $x$, the left side of the inequality above is always a non negative number. This is never less than the negative number at the right. Hence, there is $\text{ no solution .}$

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