Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Review Exercises: 69

Answer

$\left( -14,14 \right)$

Work Step by Step

Since for any $a\gt0$, $|x|\lt a$ implies $-a\lt x\lt a,$ then the given inequality, $ |x|\lt14 ,$ is equivalent to \begin{array}{l}\require{cancel} -14\lt x\lt14 .\end{array} Hence, the solution is the interval $ \left( -14,14 \right) .$
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