## Intermediate Algebra (12th Edition)

$\left( -14,14 \right)$
Since for any $a\gt0$, $|x|\lt a$ implies $-a\lt x\lt a,$ then the given inequality, $|x|\lt14 ,$ is equivalent to \begin{array}{l}\require{cancel} -14\lt x\lt14 .\end{array} Hence, the solution is the interval $\left( -14,14 \right) .$