## Intermediate Algebra (12th Edition)

a conditional equation; $x=0$
Using the properties of equality, the given equation, $x+6(x-1)-(4-x)=-10 ,$ is equivalent to \begin{array}{l}\require{cancel} x+6x-6-4+x=-10 \\\\ x+6x+x=-10+6+4 \\\\ 8x=0 \\\\ x=\dfrac{0}{8} \\\\ x=0 .\end{array} Since the solution above ended with a variable being equated to a constant, then the given equation is $\text{ a conditional equation .}$ The solution is $x=0 .$