Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Review Exercises - Page 129: 10



Work Step by Step

Using the properties of equality, in terms of $ b ,$ the given equation, $ A=\dfrac{1}{2}h(b+B) ,$ is equivalent to \begin{array}{l}\require{cancel} 2A=h(b+B) \\\\ 2A=hb+hB \\\\ 2A-hB=hb \\\\ \dfrac{2A-hB}{h}=\dfrac{hb}{h} \\\\ \dfrac{2A-hB}{h}=b \\\\ b=\dfrac{2A-hB}{h} .\end{array}
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