Answer
Either $1$ or $0$.
Work Step by Step
Let $A$ be an idempotent matrix. This means that $A^2-A=0$, so the minimal polynomial of $A$ is $m(x)=x^2-x$. The possible eigenvalues of the matrix $A$ are the zeroes of the minimal polynomials. Since the zeroes of $m(x)$ are $\{0,1\}$, the possible eigenvalues are $0$ or $1$.