Answer
$-2$
Work Step by Step
$T(e^{-2x})=(e^{-2x})'=-2e^{-2x}=-2\cdot e^{-2x}$, thus we can indeed see that $-2$ is an eigenvalue with the corresponding eigenvector of $e^{-2x}$.
Elementary Linear Algebra 7th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
1-13311-087-8
ISBN 13:
978-1-13311-087-3
Chapter 7 - Eigenvalues and Eigenvectors - 7.1 Eigenvalues and Eigenvectors - 7.1 Exercises - Page 352: 72
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