Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - 4.8 Applications of Vector Spaces - 4.8 Exercises - Page 219: 14

Answer

$$W=-3 \mathrm{e}^{2 x} \sin (3 x)-2 \cos (3 x) \mathrm{e}^{2 x}.$$

Work Step by Step

The Wronskian of $\left\{e^{2 x}, \cos 3 x\right\}$ is given by $$W=\left|\begin{array}{cc}{\mathrm{e}^{2 x}} & {\cos (3 x)} \\ {2 \mathrm{e}^{2 x}}&{-3 \sin (3 x)}\end{array}\right|=-3 \mathrm{e}^{2 x} \sin (3 x)-2 \cos (3 x) \mathrm{e}^{2 x}$$
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