Answer
$$[x]_S=\left[ \begin {array}{ccc} 8\\ -3\end {array} \right].$$
Work Step by Step
Since we have
$$x= 4(2,-1)+(0,1)=(8,-3).$$
then we can write $x$ relative to the standard basis of $R^2$ as follows
$$x= (8,-3)=8(1,0)-3(0,1) .$$
Thus, the coordinates matrix of $x$ in $R^2$ relative to the
standard basis is
$$[x]_S=\left[ \begin {array}{ccc} 8\\ -3\end {array} \right].$$