Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - 4.6 Rank of a Matrix and Systems of Linear Equations - 4.6 Exercises - Page 199: 18

Answer

A basis for the subspace is given by $$\{2,5,-3,-2 ),(0,2,-1,-7),(0,0,-1,19) \}.$$

Work Step by Step

Let $S$ be given by $$ S=\{(2,5,-3,-2 ),(-2,-3,2,-5),(1,3,-2,2) (-1,-5,3,5) \} . $$ We form the matrix $$ \left[ \begin {array}{cccc} 2&5&-3&-2\\ -2&-3&2&-5 \\ 1&3&-2&2\\ -1&-5&3&5 \end {array} \right] . $$ The reduced form of the matrix is given by $$\left[ \begin {array}{cccc} 2&5&-3&-2\\ 0&2&-1&-7 \\ 0&0&-1&19\\ 0&0&0 &0\end {array} \right] .$$ A basis for the subspace is given by $$\{2,5,-3,-2 ),(0,2,-1,-7),(0,0,-1,19) \}.$$
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