Elementary Linear Algebra 7th Edition

$S$ is not a basis for $R^3$.
The set $S=\{(0,3,-2),(4,0,3),(-8,15,-16)\}$ is not a basis for $R^3$ because $S$ is not linearly independent. For example, one can see that $$(-8,15,-16)=5(0,3,-2)-2(4,0,3).$$ Which means that $S$ is linearly dependent set of vectors.