Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 3 - Determinants - Review Exercises - Page 140: 68

Answer

the equation of the line is $$2y+3x-16=0.$$

Work Step by Step

The equation of the line is given by $$ \left|\begin{array}{rrr}{x} & {y} & {1} \\ {2} & {5} & {1} \\ {6} & {-1} & {1}\end{array}\right|= 0. $$ So, we have $$ \left|\begin{array}{rrr}{x} & {y} & {1} \\ {2} & {5} & {1} \\ {6} & {-1} & {1}\end{array}\right|= x(5+1)-y(2-6)+(-2-30)=4y+6x-32=0. $$ Hence, the equation of the line is $$2y+3x-16=0.$$
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