Answer
the equation of the line is $$2y- x-4=0.$$
Work Step by Step
The equation of the line is given by $$ \left|\begin{array}{rrr}{x} & {y} & {1} \\ {-4} & {0} & {1} \\ {4} & {4} & {1}\end{array}\right|= 0. $$ So, using the second row we calculate the determinant as follows
$$ \left|\begin{array}{rrr}{x} & {y} & {1} \\ {-4} & {0} & {1} \\ {4} & {4} & {1}\end{array}\right|= 4(y-4)-(4x-4y)=8y-4x-16=0. $$ Hence, the equation of the line is $$2y- x-4=0.$$
