Answer
The statement is correct.
Work Step by Step
Let $S$ be a singular matrix of order $n$ and $B$ a matrix of order $n$.
Then, we have:
$|SB|=|S| |B| $
Since $S$ be a singular matrix of order $n$, then $|S|=0$.
Thus, $|SB|=|S| |B| =0$
Therefore, the matrix $SB$ is a singular matrix.