Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 3 - Determinants - 3.3 Properties of Determinants - 3.3 Exercises - Page 127: 75

Answer

The matrix $A$ is orthogonal.

Work Step by Step

Since $|A|=-1$, then $A$ is invertible. $A=\left [\begin{array}{ccc} 1 & 0 & 0 \\ 0 &0&1\\ 0&1&0 \end {array} \right] $ The augmented matrix of $A$ is $A=\left [\begin{array}{ccc} -1 & 0 & 0 \\ 0 &0&-1\\ 0&-1&0 \end {array} \right] $ and $A^{-1}=(1/|A|)*adjA=(-1)* \left [\begin{array}{ccc} -1 & 0 & 0 \\ 0 &0&-1\\ 0&-1&0 \end {array} \right] =\left [\begin{array}{ccc} 1 & 0 & 0 \\ 0 &0&1\\ 0&1&0 \end {array} \right] $ we have from matrix $A$ $A^{T}=\left [\begin{array}{ccc} 1 & 0 & 0 \\ 0 &0&1\\ 0&1&0 \end {array} \right]$ Therefore, $ A^{T}= A^{-1}$ Thus the matrix $A$ is orthogonal.
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