Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 3 - Determinants - 3.3 Properties of Determinants - 3.3 Exercises - Page 125: 22

Answer

singular

Work Step by Step

Since one can show that $$\left|\begin{array}{rrr} 2&-1/2&8\\ 1&-1/4&4 \\ -5/2&3/2&8 \end{array}\right|=0,$$ then the matrix $$\left[\begin{array}{rrr} 2&-1/2&8\\ 1&-1/4&4 \\ -5/2&3/2&8\end{array}\right]$$ is singular.
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